How to use If Statement Indirectly to solve expression ?

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Indirect Use of If Statement : Expression Solving

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How to Decide Expression Contain Invisible If Statement ?
How to solve Expression such as [ x = a > 5 ] ? What will be the output after printing the value of “x” ? This typical Question comes under “Invisible / Indirect use of If Statement “.
If Expression Contain Following Operators then given expression is of type - “Invisible / Indirect use of If Statement “.

1. <
2. >
3. <=
4. >=
5. ==
6. !=

#include<stdio.h>
void main()
{
int num1 = 100,num2=200,num3;
num3 = ( num1 >= 100 ) + (num2 < 50 );
printf("%d",num3);
}

Output :

1

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How ?
Writing

num3 = ( num1 >= 100 );

is as good as writing

if( num1 >= 100 )    
   num3 = 1;
else    
   num3 = 0;

Note : While Solving Such Expression always Check whether the expression Statement is True or False. If Expression is true then Replace 1 instead of that expression otherwise replace that expression with 0
num3 can be Calculated as -

num3 = ( num1 >= 100 ) + (num2 < 50 );
num3 = 1 + (num2 < 50 );  // ( num1 >= 100 ) is True
num3 = 1 + 0;             // (num2 < 50 ) is False
num3 = 1;

Example 1 : c = !(a>=0) >= 0
Example 2 : c = !a<=!(c=b);

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