How to solve expression containing comparison and assignment operators ?

Example : Illustration of Indirect or Invisible If [ Click Here : Indirect If Statement ]

#include<stdio.h>
void main()
{
int a = 40 , b = 30 ,c;
c = !a<=!(c=b);
printf("%d",c);
}

Output :

1

How ?
Step 1 :

1. Always Solve Bracket First
2. (c = b) : Assignment Operator Assigns value of RHS to LHS i.e Assigns value of b to c
3. Replace “(c=b)” by 30

c = !a<=!30;

Step 2 :

1. “Not” Operator has Higher Priority Than “<=” Operator.
2. !a= !40 = 0
3. Replace “!a” by “0″ as we calculated .

c = 0<=!30

Step 3 :

1. As “c = 0<=!30″ contain again Two Operands , Again scan Expression from we have now Two Operators “!” and “<=”.
2. “Not” Operator has Higher Priority so
3. !30 = 0
4. Replace “!30″ by “0″
   

c = 0<=0

Step 4 :

1. Obviously 0 <= 0 is True Condition
2. Replace Whole Expression by 1

c = 1

1. Thus C = 1

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