C Program to Print 1-10 numbers without using Conditional Loops

Print 1-10 numbers without using Conditional Loop i.e without using

for Loop
while Loop
do-while Loop

This can be achieved in 3 ways :

Using Printf Statement 10 Times.
Using Recursive Function
Using goto Statement.
Recursive Main Function

Way 1 : Printf Statement 10 times

#include<stdio.h>
void main()
{
printf("1");
printf("2");
printf("3");
printf("4");
printf("5");
printf("6");
printf("7");
printf("8");
printf("9");
printf("10");
}

#include<stdio.h>

void main()

{

printf("1");

printf("2");

printf("3");

printf("4");

printf("5");

printf("6");

printf("7");

printf("8");

printf("9");

printf("10");

}

Use 10 Times Printf Statement .

Way 2 : Recursive Function

#include<stdio.h>

void printNumber(int value) {
   int i;
   printf("%d\n", value);
   i = value + 1;

   if (i > 10)
      return;
   printNumber(i);
}

void main() {
   printNumber(1);
}

#include<stdio.h>

void printNumber(int value) {

int i;

printf("%d\n", value);

i = value + 1;

if (i > 10)

return;

printNumber(i);

}

void main() {

printNumber(1);

}

Recursive function : Calling Itself .
printNumber function calls itself so it is called Recursive function .

Way 3 : Using Goto Statement

#include<stdio.h>

void main() {
   int i = 0;
   Start: i = i + 1;
   printf("%d", i);

   if (i <= 10)
      goto Start;
}

#include<stdio.h>

void main() {

int i = 0;

Start: i = i + 1;

printf("%d", i);

if (i <= 10)

goto Start;

}

Way 4 : Using Recursive Main

#include<stdio.h>

void main() {
   static int i = 1;
   if (i <= 10) {
      printf("%d", i++);
      main();
   }
}

#include<stdio.h>

void main() {

static int i = 1;

if (i <= 10) {

printf("%d", i++);

main();

}

Static variable inside a function means “once the variable has been initialized, it remains in memory until the end of the program”

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