C Program to Accept Paragraph using scanf

Accept Paragraph using scanf in C

#include<stdio.h>
int main() {
   char para[100];
   printf("Enter Paragraph : ");
   scanf("%[^\t]s", para);
   printf("Accepted Paragraph : %s", para);
   return 0;
}

#include<stdio.h>

int main() {

char para[100];

printf("Enter Paragraph : ");

scanf("%[^\t]s", para);

printf("Accepted Paragraph : %s", para);

return 0;

}

Output :[Press Tab to Stop Accepting Characters ]

Enter Paragraph : Pritesh Taral is author
of c4learn.com	
Accepted Paragraph : Pritesh Taral is author
of c4learn.com

Enter Paragraph : Pritesh Taral is author

of c4learn.com

Accepted Paragraph : Pritesh Taral is author

of c4learn.com

How ?

scanf("%[^\t]s", para);

1	scanf("%[^\t]s", para);

Here scanf will accept Characters entered with spaces.
It also accepts the Words , new line characters .
%[^\t]s represent that all characters are accepted except tab(t) , whenever t will encountered then the process of accepting characters will be terminated.

Drawbacks :

Paragraph Size cannot be estimated at Compile Time
It’s vulnerable to buffer overflows.

How to Specify Maximum Size to Avoid Overflow ?

//------------------------------------
// Accepts only 100 Characters
//------------------------------------
scanf("%10[^\t]s", para);

//------------------------------------

// Accepts only 100 Characters

//------------------------------------

scanf("%10[^\t]s", para);

Output :

Enter Paragraph : Pritesh Taral is author of C4learn
Accepted Paragraph : Pritesh Ta

1 2	Enter Paragraph : Pritesh Taral is author of C4learn Accepted Paragraph : Pritesh Ta

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C Program to Accept Paragraph using scanf

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