Program : To find equivalent capacitance of Parallel combination of capacitive circuit
#include<stdio.h> #include<conio.h> int main() { float c[10],num,Cp=0; int i; clrscr(); printf("Enter the number of Capacitors : "); scanf("%f",&num); printf("\nEnter Value of Each Capacitor : \n"); for(i=0;i<num;i++) { printf("\nC%d : ",i+1); scanf("%f",&c[i]); } for(i=0;i<num;i++) { Cp = Cp + c[i]; } printf("\nEquivalent Parallel Capacitance : %f mFarad",Cp); getch(); }
Output :
Enter the number of Capacitors : 3 Enter Value of Each Capacitor : C1 : 1.2 C2 : 1.3 C3 : 1.4 Equivalent Parallel Capacitance : 3.900000 mFarad