Add two number using pointer and Dynamic memory allocation

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Add two number using pointer and Dynamic memory allocation

#include<stdio.h>
#include<stdlib.h>
#include<conio.h>
void main()
{
int *ptr,sum=0,i;
clrscr();
// Allocate memory Equivalent to 1 integer
ptr = (int *)malloc(sizeof(int));
  for(i=0;i<2;i++)
     {
     printf("Enter number : ");
     scanf("%d",ptr);
     sum = sum + (*ptr);
     }
printf("\nSum = %d",sum);
getch();
}

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Better Version :(If At Run Memory is not available then It Will Return NULL)

#include<stdio.h>
#include<stdlib.h>
#include<conio.h>
void main()
{
int *ptr,sum=0,i;
clrscr();
// Allocate memory Equivalent to 1 integer
ptr = (int *)malloc(sizeof(int));
if(ptr==NULL)
{
  printf("\nError in Allocating Memory");
  exit(0);
}
 for(i=0;i<2;i++)
     {
     printf("Enter number : ");
     scanf("%d",ptr);
     sum = sum + (*ptr);
     }
printf("\nSum = %d",sum);
getch();
}

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Output :

Enter number : 4
Enter number : 5
Sum = 9

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Tags / Keywords : | calloc, dynamic memory allocation, malloc

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