C Program to Print Binary Numbers Pyramid Pattern

Problem Statement : Generate Following Pattern of Pyramid

1 
0 1 
1 0 1 
0 1 0 1 
1 0 1 0 1 
0 1 0 1 0 1 
1 0 1 0 1 0 1

0 1

1 0 1

0 1 0 1

1 0 1 0 1

0 1 0 1 0 1

1 0 1 0 1 0 1

#include<stdio.h>
int main() {
   int i, j;
   int count = 1;
   for (i = 1; i <= 4; i++) {
      printf("\n");
      for (j = 1; j <= i; j++) {
         printf("%d", count % 2);
         count++;
      }
      if (i % 2 == 0)
         count = 1;
      else
         count = 0;
   }
   return(0);
}

#include<stdio.h>

int main() {

int i, j;

int count = 1;

for (i = 1; i <= 4; i++) {

printf("\n");

for (j = 1; j <= i; j++) {

printf("%d", count % 2);

count++;

}

if (i % 2 == 0)

count = 1;

else

count = 0;

}

return(0);

}

Program Explanation :

We have declared some of the variables. We have declared count variable,

int count = 1;

1	int count = 1;

First and Third Line is Starting with 1 , while 2nd and 4th Line is starting with 0, So for first and third line count will be 1 and for even line number count will be equal to 0.

Line Number	Value of Count
1	1
2	0
3	1
4	0
5	1

Outer for loop will decide the line. In this pyramid we need to print 5 lines so we have for loop which can execute 5 times.

for(i=1;i<=5;i++)
    {
    printf("\n");

for(i=1;i<=5;i++)

{

printf("\n");

As each iteration of for loop is new line we need to print newline character on each line
below table explains how many times inner loop is executed -

Value of i	No of times inner Loop gets executed	Values of j
1	1	1
2	2	1 2
3	3	1 2 3
4	4	1 2 3 4

below lines will decide the value of count for next iteration -

if( i % 2 == 0)
   count=1;
else
   count=0;

if( i % 2 == 0)

count=1;

else

count=0;

Table of Content