Array of Pointer to Structure
Syntax :
struct stud{ int roll; char name[10];}*ptr[20];Explain ?
- Suppose we have to maintain database of 10 students .
- Here 10 Structures are Placed in the Memory and there base addresses are stored in Pointers .
- E.g ptr[0],ptr[1] stores the address of First & second structure respectively.
- Using the Array of Pointer the time required to access structure reduces.
- This is used in Dynamic Memory Allocation
Diagram :
Live Example :
#include<stdio.h>#include<conio.h>
struct stud{ int roll; char name[10];}*ptr[10];
//-------------------------------------void main(){int i;printf("Enter the Student Details : ");
for(i=0;i<3;i++) { ptr[i] = (struct stud *) malloc(sizeof(struct stud)); printf("nEnter the Roll Number : "); scanf("%d",&ptr[i]->roll); printf("nEnter the Name : "); scanf("%s",ptr[i]->name); }
printf("nStudent Details are : ");
for(i=0;i<3;i++) { printf("nRoll Number : %d",ptr[i]->roll); printf("nName : %s",ptr[i]->name); }getch();}Output :
Enter the Student Details :Enter the Roll Number : 1Enter the Name : Pritesh Enter the Roll Number : 2Enter the Name : Suraj Enter the Roll Number : 3Enter the Name : Aruna Student Details are :Roll Number : 1Name : PriteshRoll Number : 2Name : SurajRoll Number : 3Name : Aruna
